0=(x^2+3x+9)

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Solution for 0=(x^2+3x+9) equation: 



0=(x^2+3x+9)

We move all terms to the left:

0-((x^2+3x+9))=0

We add all the numbers together, and all the variables

-((x^2+3x+9))=0



We calculate terms in parentheses: -((x^2+3x+9)), so:

(x^2+3x+9)

We get rid of parentheses

x^2+3x+9

Back to the equation:

-(x^2+3x+9)



We get rid of parentheses

-x^2-3x-9=0

We add all the numbers together, and all the variables

-1x^2-3x-9=0

a = -1; b = -3; c = -9;
Δ = b2-4ac
Δ = -32-4·(-1)·(-9)
Δ = -27
Delta is less than zero, so there is no solution for the equation

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